∫ 0 1 x 4 5 d x = 5 x 4 5 9 = 5 x 4 5 9 | 0 1 {\displaystyle {\begin{aligned}&\int _{0}^{1}x^{\cfrac {4}{5}}dx\\[2ex]&={\cfrac {5{\sqrt[{5}]{x^{4}}}}{9}}\\[2ex]&={\cfrac {5{\sqrt[{5}]{x^{4}}}}{9}}{\bigg |}_{0}^{1}\end{aligned}}}