∫ − 1 2 ( x 3 − 2 x ) d x = x 4 4 − 2 x 2 2 | − 1 2 {\displaystyle {\begin{aligned}\int _{-1}^{2}(x^{3}-2x)dx&={\frac {x^{4}}{4}}-{\frac {2x^{2}}{2}}{\Bigg |}_{-1}^{2}\end{aligned}}}
