∫ 2 x 3 x u 2 − 1 u 2 + 1 d u {\displaystyle \int _{2x}^{3x}{\frac {u^{2}-1}{u^{2}+1}}du}
d d x [ ∫ 2 x 3 x u 2 − 1 u 2 + 1 d u ] = 3 ∗ 3 x 2 x 2 {\displaystyle {\frac {d}{dx}}\left[\int _{2x}^{3x}{\frac {u^{2}-1}{u^{2}+1}}du\right]=3*{\frac {3x^{2}}{x^{2}}}}
![{\displaystyle {\frac {d}{dx}}\left[\int _{2x}^{3x}{\frac {u^{2}-1}{u^{2}+1}}du\right]=3*{\frac {3x^{2}}{x^{2}}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/96885d7a4f497df97ed59ccba44f46e89d84c8a8)