∫ ( x 3 + x 2 3 ) d x = ∫ ( x 1 3 + x 2 3 ) d x = ( x f r a c 1 3 + 1 1 3 + 1 ) {\displaystyle {\begin{aligned}\int \left({\sqrt {x^{3}}}+{\sqrt[{3}]{x^{2}}}\right)dx&=\int \left(x^{\frac {1}{3}}+x^{\frac {2}{3}}\right)dx\\[2ex]&=\left({\frac {x^{frac{1}{3}+1}}{{\frac {1}{3}}+1}}\right)\\[2ex]\end{aligned}}}