∫ 0 2 ( x − 1 ) 25 d x ∫ t 25 d t t 25 26 ( x − 1 ) 26 26 | 0 2 {\displaystyle {\begin{aligned}&\int _{0}^{2}({x-1})^{25}dx\\[2ex]&\int {t^{25}}dt\\[2ex]&{\cfrac {t^{25}}{26}}\\[2ex]&{\cfrac {(}{x-1}})^{26}{26}{\bigg |}_{0}^{2}\end{aligned}}}