∫ 0 2 ( x − 1 ) 25 d x ∫ t 25 d t t 25 26 ( x − 1 ) 26 26 | 0 2 ( 2 − 1 ) 26 26 − ( 0 − 1 ) 26 26 = 0 {\displaystyle {\begin{aligned}&\int _{0}^{2}({x-1})^{25}dx\\[2ex]&\int {t^{25}}dt\\[2ex]&{\cfrac {t^{25}}{26}}\\[2ex]&{\cfrac {(x-1)^{26}}{26}}{\bigg |}_{0}^{2}\\[2ex]&{\cfrac {(2-1)^{26}}{26}}-{\cfrac {(0-1)^{26}}{26}}\\[2ex]&=0\end{aligned}}}