2 ( sin ( π 3 ) ) − 3 ( tan ( π 6 ) ) {\displaystyle 2(\sin({\frac {\pi }{3}}))-3(\tan({\frac {\pi }{6}}))}
2 ( 3 2 ) − 3 ( 1 2 3 2 ) {\displaystyle 2({\frac {\sqrt {3}}{2}})-3({\frac {\frac {1}{\cancel {2}}}{\frac {\sqrt {3}}{\cancel {2}}}})}
2 ( 3 2 ) − 3 ( 1 3 ) {\displaystyle 2({\frac {\sqrt {3}}{2}})-3({\frac {1}{\sqrt {3}}})}
2 3 2 − 3 3 ( 3 ) {\displaystyle {\frac {2{\sqrt {3}}}{2}}-{\frac {3}{\sqrt {3}}}({\sqrt {3}})}
2 3 2 − 3 3 3 {\displaystyle {\frac {{\cancel {2}}{\sqrt {3}}}{\cancel {2}}}-{\frac {{\cancel {3}}{\sqrt {3}}}{\cancel {3}}}}
3 − 3 = 0 {\displaystyle {\sqrt {3}}-{\sqrt {3}}=0}