∫ x x 2 + 1 d x = x 2 + 1 + c {\displaystyle \int {\frac {x}{\sqrt {x^{2}+1}}}dx={\sqrt {x^{2}+1}}+c}
d d x ( x 2 + 1 ) ( 1 2 ) + c {\displaystyle {\frac {d}{dx}}(x^{2}+1)^{\left({\frac {1}{2}}\right)}+c}
