∫ x x 2 + 1 d x = x 2 + 1 + c {\displaystyle \int {\frac {x}{\sqrt {x^{2}+1}}}dx={\sqrt {x^{2}+1}}+c}
[ d d x ( x 2 + 1 ) 1 2 + c ] {\displaystyle \left[{\frac {d}{dx}}(x^{2}+1)^{\frac {1}{2}}+c\right]}
![{\displaystyle \left[{\frac {d}{dx}}(x^{2}+1)^{\frac {1}{2}}+c\right]}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/b2d1d939e0063454bfc13130a372004e6f5fdf6a)