5.3 The Fundamental Theorem of Calculus/8

Failed to parse (unknown function "\break"): {\displaystyle g(x)=\int_{3}^{x}e^{t^2-t}dt \break \frac{d}{dx}\left[g(x)\right] = \frac{d}{dx}\left[\int_{3}^{x}e^{t^2-t}dt\right]=1e^{x^2-x}-0e^{3^2-3}=e^{x^2-x} \text{Therefore, } g'(x)=e^{x^2-x} }