5.3 The Fundamental Theorem of Calculus/17

FTC #1 $y=\int \limits _{1-3x}^{1}{\frac {x^{3}}{(1+u^{2})}}dx$

$G(x)=f(x)$

so $y=\int \limits _{1-3x}^{1}{\frac {1}{(1+u^{2})}}x^{3},dx$

= $(0)*f(1)-(-3)*f(1-3x)$