∫ 0 π 4 sec 2 ( t ) d t = tan ( t ) | 0 π 4 = tan ( π 4 ) − tan ( 0 ) = 1 − 0 = 1 {\displaystyle \int _{0}^{\frac {\pi }{4}}\sec ^{2}(t)\,dt=\tan(t){\bigg |}_{0}^{\frac {\pi }{4}}=\tan \left({\frac {\pi }{4}}\right)-\tan(0)=1-0=1}