∫ ( x 4 − 1 2 x 3 + 1 4 x − 2 ) d x = x 5 5 − x 4 8 + x 2 8 − 2 x + C {\displaystyle \int \left(x^{4}-{\frac {1}{2}}x^{3}+{\frac {1}{4}}x-2\right)dx={\frac {x^{5}}{5}}-{\frac {x^{4}}{8}}+{\frac {x^{2}}{8}}-2x+C}
