f ( x ) = x 2 = x 3 + ( x + 1 ) 3 = ∫ 1 5 f ( x ) d x = ( 1 x 2 ) {\displaystyle {\begin{aligned}f(x)&=x^{2}\\[2ex]&=x^{3}+(x+1)^{3}\\[2ex]&=\int _{1}^{5}f(x)\,dx\\[2ex]&=\left({\frac {1}{x^{2}}}\right)\end{aligned}}}