f ( θ ) = sin ( θ ) {\displaystyle f{(\theta )}=\sin {(\theta )}} g ( θ ) = cos ( θ ) {\displaystyle g{(\theta )}=\cos {(\theta )}}
if θ = 60 ∘ {\displaystyle \theta =60^{\circ }}
f ( θ ) = sin 60 ∘ = 3 2 g ( θ ) = cos 60 ∘ = 1 2 {\displaystyle f{(\theta )}=\sin {60^{\circ }}={\frac {\sqrt {3}}{2}}g{(\theta )}=\cos {60^{\circ }}={\frac {1}{2}}}
