5.3 The Fundamental Theorem of Calculus/37: Difference between revisions

Revision as of 19:00, 25 August 2022

FTC # 2- the ${\frac {d}{dx}}[\int \limits _{a(x)}^{b(x)}F(x)dx]$ is F(b)-F(a) where F is the antiderivitive of f such that F^prime=f

$\int \limits _{1/2}^{({\sqrt {3}})/2}{\frac {6}{({\sqrt {1-x^{2}}})}}du$

Revision as of 19:00, 25 August 2022 (view source) Juanr69976@students.laalliance.org (talk \| contribs) No edit summary ← Older edit		Revision as of 19:00, 25 August 2022 (view source) Juanr69976@students.laalliance.org (talk \| contribs) No edit summary Newer edit →
Line 1:		Line 1:
	FTC # 2- the <math>\frac{d}{dx}[\int\limits_{a(x)}^{b(x)}F(x)dx]</math> is F(b)-F(a) where F is the antiderivitive of f such that F^/prime=f		FTC # 2- the <math>\frac{d}{dx}[\int\limits_{a(x)}^{b(x)}F(x)dx]</math> is F(b)-F(a) where F is the antiderivitive of f such that F^prime=f