5.3 The Fundamental Theorem of Calculus/31: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
| Line 1: | Line 1: | ||
<math>\int_{0}^{\frac{\pi\}{4}}\sec^2(t)dt =tan(\frac{\pi\}{4})-tan(0) =1-0 = 1</math> | <math>\int_{0}^{\frac{\pi\}{4}}\sec^2(t)dt=tan(\frac{\pi\}{4})-tan(0)=1-0=1</math> | ||
Revision as of 19:08, 25 August 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{0}^{\frac{\pi\}{4}}\sec^2(t)dt=tan(\frac{\pi\}{4})-tan(0)=1-0=1}