5.5 The Substitution Rule/1: Difference between revisions

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\begin{align}
\begin{align}


& \int{e^-x} dx \\[2ex], u=-x
& \int{e^{-x}} dx, \quad u=-x \\[2ex]  


& \int{e^-x} dx \\[2ex]
& u=-x \\ [2ex]


& \-int{e^u} du \\[2ex]
& du=-dx\\ [2ex]  


& -\e^u du\\[2ex]
\end{align}
</math>
 
 
<math>


&= -\e^-x+C
\int{e^{-x}} dx = -\int{e^{u}} du = -e^{u} +C  = -e^{-x}+C


\end{align}
</math>
</math>

Latest revision as of 19:55, 1 September 2022