5.3 The Fundamental Theorem of Calculus/31: Difference between revisions
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\int_{0}^{\frac{\pi}{4}}\sec^{2}(t)\,dt = \tan\left(\frac{\pi}{4}\right)-\tan(0)=1-0=1 | \int_{0}^{\frac{\pi}{4}}\sec^{2}(t)\,dt = \tan(t)\bigg|_{0}^{\frac{\pi}{4}=\tan\left(\frac{\pi}{4}\right)-\tan(0)=1-0=1 | ||
</math> | </math> | ||
Revision as of 21:24, 6 September 2022
Failed to parse (syntax error): {\displaystyle \int_{0}^{\frac{\pi}{4}}\sec^{2}(t)\,dt = \tan(t)\bigg|_{0}^{\frac{\pi}{4}=\tan\left(\frac{\pi}{4}\right)-\tan(0)=1-0=1 }