5.5 The Substitution Rule/1: Difference between revisions
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\begin{align} | \begin{align} | ||
& \int{e^{-x}} dx ,u=-x \\[2ex] | & \int{e^{-x}} dx, \quad u=-x \\[2ex] | ||
& u=-x \\ [2ex] | & u=-x \\ [2ex] | ||
& du=-dx\\ [2ex] | & du=-dx\\ [2ex] | ||
\end{align} | |||
</math> | |||
<math> | |||
\int{e^{-x}} dx = -\int{e^{u}} du = -e^{u} +C = -e^{-x}+C | |||
</math> | </math> | ||
Latest revision as of 19:55, 1 September 2022
![{\displaystyle {\begin{aligned}&\int {e^{-x}}dx,\quad u=-x\\[2ex]&u=-x\\[2ex]&du=-dx\\[2ex]\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/6e256caafce417840d30b15cc0dc0acbf3e56a1e)
