5.4 Indefinite Integrals and the Net Change Theorem/25

${\begin{aligned}&\int _{-2}^{2}({3u+1})^{2}du\\[2ex]&=\int {3u^{2}+6u+1}{du}\\[2ex]&={3u^{3}+3u^{2}+u}{\bigg |}_{-2}^{2}\\[2ex]&={3\cdot 2^{3}+\cdot 2^{2}+2-3\cdot -2^{3}+3\cdot -2^{2}-2}\\[2ex]&={52}\end{aligned}}$