6.2 Trigonometric Functions: Unit Circle Approach/47: Difference between revisions

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\begin{align}
\begin{align}


\sin{\left(\frac{2\pi}{3}\right)} &= \frac{\sqrt{3}}{2} & \csc{\left(\frac{2\pi}{3}\right)} &= \frac{{1}} \frac{\sqrt{3}}{2} \cdot{2} = \frac{2}{\sqrt{3}} \cdot{\sqrt{3}} \\[2ex]
\sin{\left(\frac{2\pi}{3}\right)} &= \frac{\sqrt{3}}{2} & \csc{\left(\frac{2\pi}{3}\right)} &= \frac{{1}} \frac{\sqrt{3}}{2} \cdot{2} = \frac{2}{\sqrt{3}} \cdot{\sqrt{3}} = \frac{2\sqrt{3}}{3} \\[2ex]


\cos{\left(\frac{2\pi}{3}\right)} &= -\frac{1}{2} & \sec{\left(\frac{5\pi}{6}\right)} &= \frac{{2}}{-\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}} = -\frac{2\sqrt{3}}{3}\\[2ex]  
\cos{\left(\frac{2\pi}{3}\right)} &= -\frac{1}{2} & \sec{\left(\frac{5\pi}{6}\right)} &= \frac{{2}}{-\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}} = -\frac{2\sqrt{3}}{3}\\[2ex]  

Revision as of 16:17, 1 September 2022