5.4 Indefinite Integrals and the Net Change Theorem/25: Difference between revisions
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\begin{align} | \begin{align} | ||
\int_{-2}^{2}({3u+1})^2 du = \int {3u^2+6u+1} {du} \\[2ex] | |||
&= {3u^3+3u^2+u}\bigg|_{-2}^{2} \\[2ex] | &= {3u^3+3u^2+u}\bigg|_{-2}^{2} \\[2ex] | ||
| Line 9: | Line 9: | ||
&= {52} | &= {52} | ||
\end{align} | \end{align} | ||
</math> | </math> | ||
Revision as of 17:39, 7 September 2022
![{\displaystyle {\begin{aligned}\int _{-2}^{2}({3u+1})^{2}du=\int {3u^{2}+6u+1}{du}\\[2ex]&={3u^{3}+3u^{2}+u}{\bigg |}_{-2}^{2}\\[2ex]&={3\cdot 2^{3}+\cdot 2^{2}+2-3\cdot -2^{3}+3\cdot -2^{2}-2}\\[2ex]&={52}\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/5e3610e518e3d689131fc3d858acd28753a4725e)