5.3 The Fundamental Theorem of Calculus/37: Difference between revisions

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37) <math>\int\limits_{1/2}^{(\sqrt{3})/2}\frac{6}{(\sqrt{1-t^2})} dt </math>
37) <math>\int\limits_{1/2}^{(\sqrt{3})/2}\frac{6}{(\sqrt{1-t^2})} dt </math>


using the rule we get 6sin^-1(x)
using the rule we get  
<math>6sin^-1(x)</math>


[[5.3 The Fundamental Theorem of Calculus/1|1]]
[[5.3 The Fundamental Theorem of Calculus/1|1]]

Revision as of 19:02, 25 August 2022

FTC # 2- the is F(b)-F(a) where F is the antiderivitive of f such that

37)

using the rule we get

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