5.3 The Fundamental Theorem of Calculus/31: Difference between revisions

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<math>\int_{0}^{\frac{\pi\}{4}}\sec^2(t)dt
<math>\int_{0}^{\frac{\pi\}{4}}\sec^2(t)dt
 
=tan(\frac{\pi\}{4})-tan(0)
= tan(\frac{\pi\}{4})-tan(0)
=1-0 = 1</math>
 
= 1-0 = 1</math>

Revision as of 19:08, 25 August 2022

Failed to parse (syntax error): {\displaystyle \int_{0}^{\frac{\pi\}{4}}\sec^2(t)dt =tan(\frac{\pi\}{4})-tan(0) =1-0 = 1}