5.3 The Fundamental Theorem of Calculus/31: Difference between revisions
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<math>\int_{0}^{\frac{\pi\}{4}}\sec^2(t)dt=tan(\frac{\pi\}{4})-tan(0)=1-0=1</math> | <math> | ||
\int_{0}^{\frac{\pi\}{4}}\sec^2(t)dt &= tan(\frac{\pi\}{4})-tan(0) &= 1-0 &= 1 | |||
</math> | |||
Revision as of 19:13, 25 August 2022
Failed to parse (syntax error): {\displaystyle \int_{0}^{\frac{\pi\}{4}}\sec^2(t)dt &= tan(\frac{\pi\}{4})-tan(0) &= 1-0 &= 1 }