5.3 The Fundamental Theorem of Calculus/31: Difference between revisions

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Evaluate the integral
\int_{0}^\frac{\pi}{4}sec^{2}(t)dt
<math>
<math>


\int_{0}^{\frac{(\pi\)(4)}\sec^{2}(t)dt &= tan(\frac{\pi\}{4})-tan(0) &= 1-0 &= 1
\int_{0}^\frac{\pi}{4}sec^{2}(t)dt= tan(\frac{\pi}{4})-tan(0)=1-0=1


</math>
</math>

Revision as of 19:28, 25 August 2022

Evaluate the integral

\int_{0}^\frac{\pi}{4}sec^{2}(t)dt