5.4 Indefinite Integrals and the Net Change Theorem/25: Difference between revisions

Revision as of 19:10, 26 August 2022

${\begin{aligned}&\int _{-2}^{2}({3u+1})^{2}du\\[2ex]&\int {3u^{2}+6u+1}{du}\end{aligned}}$

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	& \int_{-2}^{2}({3u+1})^2 du \\[2ex]		& \int_{-2}^{2}({3u+1})^2 du \\[2ex]

	& \int {3u^2+6u+1} du		& \int {3u^2+6u+1} {du}