5.4 Indefinite Integrals and the Net Change Theorem/17: Difference between revisions

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  <math>\int_{}^{}1+\frac{sin^2x}{cos^2x}dx</math> =  
  <math>\int_{}^{}1+\frac{sin^2x}{cos^2x}dx</math> =  
<math>\int_{}^{}\frac{cos^2x+sin^2x}{cos^2x}dx</math> =<math>\cos^2x+sin^2x=1</math> thus,  
<math>\int_{}^{}\frac{cos^2x+sin^2x}{cos^2x}dx</math> =<math>\cos^2x+sin^2x=1</math> thus,  
<math>\int_{}^{}frac{1}{cos^2x}dx</math>





Revision as of 06:54, 29 August 2022

17) =

 = 

= thus,


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