5.5 The Substitution Rule/1: Difference between revisions

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& \int{e^-x} dx \\[2ex]
& \int{e^-x} dx \\[2ex]
& \-int{e^u} du \\[2ex]
& -\e^u du\\[2ex]
&= -\e^-x+C


\end{align}
\end{align}
</math>
</math>

Revision as of 19:23, 1 September 2022