5.5 The Substitution Rule/1: Difference between revisions
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& \int{e^{-x}} dx = | & \int{e^{-x}} dx = | ||
& | & -\int{e^{u}} du = | ||
& | & -e^{u} du = | ||
& | & -e^{-x}+C | ||
\end{align} | \end{align} | ||
</math> | </math> | ||
Revision as of 19:37, 1 September 2022
![{\displaystyle {\begin{aligned}&\int {e^{-x}}dx,u=-x\\[2ex]&u=-x\\[2ex]&du=-dx\\[2ex]&\int {e^{-x}}dx=&-\int {e^{u}}du=&-e^{u}du=&-e^{-x}+C\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/c2bf3f99e517a42ebfc4ffc78fd90bb399ebb6fa)