5.5 The Substitution Rule/1: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
| Line 2: | Line 2: | ||
\begin{align} | \begin{align} | ||
& \int{e^{-x}} dx ,u=-x \\[2ex] | & \int{e^{-x}} dx, \quad u=-x \\[2ex] | ||
& u=-x \\ [2ex] | & u=-x \\ [2ex] | ||
Revision as of 19:51, 1 September 2022
![{\displaystyle {\begin{aligned}&\int {e^{-x}}dx,\quad u=-x\\[2ex]&u=-x\\[2ex]&du=-dx\\[2ex]&\int {e^{-x}}dx\\[2ex]&=-\int {e^{u}}du\\[2ex]&=-e^{u}du\\[2ex]&=-e^{-x}+C\\[2ex]\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/57ada9a9774bd73c51c30bacb4c64030292afea1)