5.3 The Fundamental Theorem of Calculus/17: Difference between revisions

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FTC #1- <math>G(x)=f^\prime(x)</math>  or in other words <math>\frac{d}{dx}\left[\int\limits_{a(x)}^{b(x)}F(x)dx\right]</math> is <math>\ b^\prime(x)*f(b(x))-a^\prime(x)*f(a(x))</math>
<math>g(x)=\int_{1-3x}^{1}\frac{u^3}{(1+u^2)} du</math>
 
17) <math>g(x)=\int\limits_{1-3x}^{1}\frac{u^3}{(1+u^2)} du</math>


<math>g\prime(x)=\frac{d}{dx}\left(\int\limits_{1-3x}^{1}\frac{u^3}{(1+u^2)} du\right) =(0)*f(1)-(-3)*f(1-3x)</math>
<math>g\prime(x)=\frac{d}{dx}\left(\int\limits_{1-3x}^{1}\frac{u^3}{(1+u^2)} du\right) =(0)*f(1)-(-3)*f(1-3x)</math>

Revision as of 20:21, 6 September 2022

which is equal to

which is=

or simplified to 



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