5.4 Indefinite Integrals and the Net Change Theorem/25: Difference between revisions

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\begin{align}
\begin{align}


\int_{-2}^{2}({3u+1})^2 du = \int {3u^2+6u+1} {du} \\[2ex]
\int_{-2}^{2}({3u+1})^2 du = \int {9u^2+6u+1} {du} \\[2ex]


&= {3u^3+3u^2+u}\bigg|_{-2}^{2} \\ [2ex]
&= {3u^3+3u^2+u}\bigg|_{-2}^{2} \\ [2ex]

Revision as of 19:13, 7 September 2022