6.1 Areas Between Curves/22

${\begin{aligned}&\color {red}\mathbf {y=\sin({\frac {\pi x}{2}})} &\color {royalblue}\mathbf {y=x} \\\end{aligned}}$

${\begin{aligned}\sin({\frac {x\pi }{2}})&=x\\x&=0\\x&=1\\\end{aligned}}$

$\int _{0}^{1}\left[\sin \left({\frac {x\pi }{2}}\right)-x\right]dx$