∫ − 2 2 ( 3 u + 1 ) 2 d u ∫ 3 u 2 + 6 u + 1 d u 3 u 3 + 3 u 2 + u | − 2 2 {\displaystyle {\begin{aligned}&\int _{-2}^{2}({3u+1})^{2}du\\[2ex]&\int {3u^{2}+6u+1}du\\[2ex]&{3u^{3}+3u^{2}+u}{\bigg |}_{-2}^{2}\end{aligned}}}