FTC # 2- the d d x [ ∫ a ( x ) b ( x ) F ( x ) d x ] {\displaystyle {\frac {d}{dx}}[\int \limits _{a(x)}^{b(x)}F(x)dx]} is F(b)-F(a) where F is the antiderivitive of f such that F ′ = f {\displaystyle F^{\prime }=f}
∫ 1 / 2 ( 3 ) / 2 6 ( 1 − x 2 ) d u {\displaystyle \int \limits _{1/2}^{({\sqrt {3}})/2}{\frac {6}{({\sqrt {1-x^{2}}})}}du}
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