∫ e − x d x , u = − x u = − x d u = − d x ∫ e − x d x {\displaystyle {\begin{aligned}&\int {e^{-x}}dx,\quad u=-x\\[2ex]&u=-x\\[2ex]&du=-dx\\[2ex]&\int {e^{-x}}dx\\[2ex]\end{aligned}}}
− ∫ e u d u = − e u = − e − x + C {\displaystyle -\int {e^{u}}du=-e^{u}=-e^{-x}+C}
![{\displaystyle {\begin{aligned}&\int {e^{-x}}dx,\quad u=-x\\[2ex]&u=-x\\[2ex]&du=-dx\\[2ex]&\int {e^{-x}}dx\\[2ex]\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/6974fd3b5deb74f43781d16201516181c7b93c78)
